I'm stuck on how to begin this problem...

Let (c1, c2) be a solution to the 2x2 system

A11X1 + A12X2 = 0

A21X1 + A22X2 = 0

Show that for any real number alpha (a) the ordered pair (ac1, ac2) is also a solution.

Printable View

- Mar 30th 2008, 03:59 PMpakmanShowing a solution for system of equations
I'm stuck on how to begin this problem...

Let (c1, c2) be a solution to the 2x2 system

A11X1 + A12X2 = 0

A21X1 + A22X2 = 0

Show that for any real number alpha (a) the ordered pair (ac1, ac2) is also a solution. - Mar 30th 2008, 05:03 PMteuthid
Plug in $\displaystyle (ac_1,ac_2)$...

$\displaystyle

A_{11}(ac_1)+A_{12}(ac_2)$

$\displaystyle =a\left[A_{11}(c_1)+A_{12}(c_2)\right]$

$\displaystyle =a[0]$

$\displaystyle =0$

Therefore, if $\displaystyle A_{11}(c_1)+A_{12}(c_2)=0$, then $\displaystyle (ac_1,ac_2)$ is also a solution to $\displaystyle A_{11}x_1+A_{12}x_2=0$.

then repeat the process of the second equation. This process can be done more quickly if you use matrix notation:

$\displaystyle \vec{c}$ is a solution to $\displaystyle A\vec{x}=\vec{0}$

$\displaystyle \rightarrow A\vec{c}=\vec{0}$

so, if we test $\displaystyle a\vec{c}$...

$\displaystyle A(a\vec{c})=aA\vec{c}=a\vec{0}=\vec{0}$

therefore $\displaystyle a\vec{c}$ is also a solution to $\displaystyle A\vec{x}=\vec{0}$