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Math Help - Arithmetic tables...?!?

  1. #1
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    Question Arithmetic tables...?!?

    Hi

    Any help would be greatly appreciated!
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  2. #2
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    Hello, skywalker!

    Given this multiplication table:

    . . \begin{array}{c|ccccccc}<br />
\times & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline<br />
0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\<br />
1 & 0 & 1 & 2 & 3 & 4 & 5 & 6 \\<br />
2 & 0 & 2 & 4 & 6 & 1 & 3 & 5 \\<br />
3 & 0 & 3 & 6 & 2 & 5 & 1 & 4 \\<br />
4 & 0 & 4 & 1 & 5 & 2 & 6 & 3 \\<br />
5 & 0 & 5 & 3 & 1 & 6 & 4 & 2 \\<br />
6 & 0 & 6 & 5 & 4 & 3 & 2 & 1 \end{array}

    Find the solutions of: x^2\:=\:3
    . . or explain why there are none.

    We want a number x so that: . x\cdot x \:=\:3


    But we find that:
    . . \begin{array}{ccc}0\cdot0 &=& 0 \\ 1\cdot1 &=&1 \\ 2\cdot2 &=&4 \\ 3\cdot3 &=& 2 \\ 4\cdot4 &=& 2 \\ 5\cdot5 &=& 4 \\ 6\cdot6 &=&1 \end{array}

    There are no cases where: x\cdot x \:=\:3
    . . Therefore, there are no solutions.

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