If n is equivalent to n' and m is equivalent to m', prove that (n+m) is equivalent to (n'+m').

Printable View

- Mar 11th 2008, 05:11 PMnatesterequivalence
If n is equivalent to n' and m is equivalent to m', prove that (n+m) is equivalent to (n'+m').

- Mar 11th 2008, 06:55 PMThePerfectHacker
How is equivalence defined here?

- Mar 11th 2008, 08:11 PMnatester
I have a def. that says that if {a_n} is a convergent sequence and {a_n}-{b_n} is a null sequence then {a_n} is equivalent to {b_n}