# Thread: Finding the roots of a 6-degree polynomial

1. ## Finding the roots of a 6-degree polynomial

Hello,
I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine.

Qx amd mx are defined values, Fx is the variable. Fx^6 and Fx^2 are the degree polynomial...Fx^5, Fx^4, Fx^3, Fx^1 are multiply by 0.

Example: mx=6.3, Qx=0.4 ... this would give the results of
A = 0.4890380
B = 0.788825-0.86129i
C = 0.788825+0.86129i

Thanks,
ZeroKool

2. ## Re: Finding the roots of a 6-degree polynomial

I mentioned something about this on another Forum. Are you saying that "mx" is not "m" times "x", but a constant of some kind?

-Dan