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Thread: Finding the roots of a 6-degree polynomial

  1. #1
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    Finding the roots of a 6-degree polynomial

    Hello,
    I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine.

    Finding the roots of a 6-degree polynomial-equation.png

    Qx amd mx are defined values, Fx is the variable. Fx^6 and Fx^2 are the degree polynomial...Fx^5, Fx^4, Fx^3, Fx^1 are multiply by 0.

    Example: mx=6.3, Qx=0.4 ... this would give the results of
    A = 0.4890380
    B = 0.788825-0.86129i
    C = 0.788825+0.86129i

    Thanks,
    ZeroKool
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  2. #2
    Forum Admin topsquark's Avatar
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    Re: Finding the roots of a 6-degree polynomial

    I mentioned something about this on another Forum. Are you saying that "mx" is not "m" times "x", but a constant of some kind?

    -Dan
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