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Thread: Möbius transformation problem

  1. #1
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    Möbius transformation problem

    Find a Möbius tranformation f such that:

    f(0)=1
    f'(0)=2
    f''(0)=3

    I know the solution is: f(z)= (5z+4)/(4-3z) but I don't know how to get to it. Thanks for you help!
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  2. #2
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    Re: Möbius transformation problem

    You know, I hope, that a Moebius transformation is of the form $\displaystyle f(z)=\frac{z+ b}{cz+ d}$ (you appear to have it in the form $\displaystyle \frac{a'z+ b'}{c'z+ d'}$ but my coefficients are the result of dividing both numerator and denominator by a').
    From that determine f'(z) and f''(z). Setting f(z)= 1, f'(z)= 2, and f''(z)= 3 gives three equations to solve for b, c, and d.
    Thanks from topsquark
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