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Thread: Easy boolen algebra

  1. #1
    Junior Member TriForce's Avatar
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    Easy boolen algebra

    How do I simplify:
    a'bc'+b'c'

    Mathematica code
    Code:
    BooleanMinimize[! a && b && ! c || ! b && ! c]
    Wolfram link

    Answer should be:
    a'c' + b'c'
    Last edited by TriForce; Apr 21st 2018 at 05:17 AM.
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  2. #2
    Junior Member Walagaster's Avatar
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    Re: Easy boolen algebra

    Are you familiar with the formula $a + \bar{a} b = a + b$? Easy to see with a Venn diagram. Use that appropriately after factoring out c'.
    Thanks from topsquark
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  3. #3
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    Re: Easy boolen algebra

    Take c' as a common factor

    c'(a'b + b')

    then as Walagaster said, a'b + b' = a' + b' (if you have a variable alone with OR, all its complement will be gone!)

    c'(a'b + b') = c'(a' + b') = c'a' + c'b'

    That was one way to solve the equation. Another method is that you can use a k-map

    I hope that you are familiar of how to use the k-map

    According to this simple k-map, all you have to do is to collect each two 1's together.

    Last edited by joshuaa; Apr 28th 2018 at 05:24 PM.
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