Hi,

I have a problem in integrating the FB5 distribution. The FB5's probability density function is given by $\displaystyle f(x)=\frac{1}{c(\kappa, \beta)}\exp[\kappa \gamma_1 x +\beta[(\gamma_2 x)^2 - (\gamma_3 x)^2]]$. We know that $\displaystyle \gamma_1$ represents the mean direction of the distribution and that $\displaystyle \gamma_2$ and $\displaystyle \gamma_3$ represent the major and minor axes respectively. The three columns $\displaystyle \gamma_1$, $\displaystyle \gamma_2$ and $\displaystyle \gamma_3$form an orthogonal (rotation) 3x3 matrix.

I would like to integrate this PDF and therefore I need to express its exponent in polar coordinates. I know that $\displaystyle \gamma_1 x$ can be expressed as:$\displaystyle \gamma_1 x= \cos(\theta) \cos(\theta_o) + \sin(\theta) \sin(\theta_o) \cos(\phi - \phi_o)$ since it is the vector dot product of two 3d vectors. In the above $\displaystyle \gamma_1 = [\sin(\theta_o) \cos(\phi_o) \sin(\theta_o) \sin(\phi_o) \cos(\theta_o) ]$ and $\displaystyle x= [\sin(\theta) \cos(\phi) \sin(\theta) \sin(\phi) \cos(\theta) ]$.

How can we express the$\displaystyle \gamma_2 x$ and $\displaystyle \gamma_3 x$ in a similar way?

Do you think that the following form would be correct? :$\displaystyle \gamma_2 x= \cos(\theta) \cos(\theta major) + \sin(\theta) \sin(\theta major) \cos(\phi - \phi major)$...same for $\displaystyle \gamma_3 x$????. However, I have read that one needs to define only one angle to specify the major and minor axes. This is very confusing to me. As a result, I am not sure if I can express $\displaystyle \gamma_2 x$ and $\displaystyle \gamma_3 x$ as stated above.Please advise!!!!!!!!

Many Thanks

BR

Alex.