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Thread: arithmetic progression

  1. #1
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    arithmetic progression

    hi everyone, this actually is question of arithmetic progression, but it seems like a geometric progression , which is...
    If 5 x 5∧4 x 5∧6 x...x 5∧2p =(0.04)∧-28 , determine the value of p....
    i used formula geometric progression, but it cant work as i get p =0, but the answer given is p=7
    anyone know how to do this?

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  2. #2
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    Re: arithmetic progression

    $\wedge $ is the logical AND operator. I'm not sure what you are trying to write, but I'm not understanding the question.
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  3. #3
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    Re: arithmetic progression

    Maybe meant as the exponentiation caret ... ^ ... symbol?

    $5^2 \cdot 5^4 \cdot 5^6 \cdot ... \cdot 5^{2p} = \left(\dfrac{1}{25}\right)^{-28} = 5^{56}$

    $2+4+6+ ... +2p = 56$

    $1+2+3+ ... + p = 28$

    $p=7$

    fyi ... this is not Advanced Algebra. More likely Precalculus.
    Last edited by skeeter; Jul 28th 2017 at 04:49 AM.
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