1. ## arithmetic progression

hi everyone, this actually is question of arithmetic progression, but it seems like a geometric progression , which is...
If 5² x 5∧4 x 5∧6 x...x 5∧2p =(0.04)∧-28 , determine the value of p....
i used formula geometric progression, but it cant work as i get p =0, but the answer given is p=7
anyone know how to do this?

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2. ## Re: arithmetic progression

$\wedge$ is the logical AND operator. I'm not sure what you are trying to write, but I'm not understanding the question.

3. ## Re: arithmetic progression

Maybe meant as the exponentiation caret ... ^ ... symbol?

$5^2 \cdot 5^4 \cdot 5^6 \cdot ... \cdot 5^{2p} = \left(\dfrac{1}{25}\right)^{-28} = 5^{56}$

$2+4+6+ ... +2p = 56$

$1+2+3+ ... + p = 28$

$p=7$

fyi ... this is not Advanced Algebra. More likely Precalculus.