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Thread: How to solve following summation question

  1. #1
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    How to solve following summation question

    How can I solve the following
    How to solve following summation question-solvable.jpg

    Note that I know if the sum starts from m=0, the term is equal to ex. However, if m = n, where m>n and both are positive integers.
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  2. #2
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    Re: How to solve following summation question

    Quote Originally Posted by sjaffry View Post
    How can I solve the following
    Click image for larger version. 

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    Note that I know if the sum starts from m=0, the term is equal to ex. However, if m = n, where m>n and both are positive integers.
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  3. #3
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    Re: How to solve following summation question

    How I would do it:

    $\displaystyle \sum_{m=n}^\infty \dfrac{x^m}{m!} = \sum_{m=0}^\infty \dfrac{x^m}{m!} - \sum_{m=0}^{n-1} \dfrac{x^m}{m!} = e^x-1-x-\dfrac{x^2}{2!} - \ldots - \dfrac{x^{n-1}}{(n-1)!}$
    Thanks from topsquark and sjaffry
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