
Originally Posted by
Deadstar
Find the solution of the system
x (with a dot above it, dont know the Latex) = 2x - y
y (same, with dot) = 3x - 2y
so matrix A =;
[2 -1]
[3 -2]
satisfying x(0) = 2 and y(0) = -1.
Now i got the eigenvalues to be $\displaystyle \pm 1$
so how to i calculate the eigenvectors given that;
for $\displaystyle \lambda = 1$ we have A - I =;
[1 -1]
[3 -3]
and for $\displaystyle \lambda = -1$ we have A - I =;
[3 -1]
[3 -1]
I cant seem to find any examples that actually explain hows its done, every example just seems to state the eigenvector straight after stating the matrices.
Any help? Cheers.