Can i get help with creating an equation for the two lines in on the graph above, the points are to the side of the graph
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tell you what you write the data points as text as $\{x_1, y_1\}, \{x_2, y_2\}, $ etc. and I'll fit a curve for you. I'm not going to type all that in from the picture though.
Ok thank you!!!! Curve one: {32,0},{35 1.52},{45,7.62},{55,12.73},{90,21.08} Curve two: {32,24.64},{35,26.16}.{45,32.26},{55,37.34},{90,45 .72}
Ok thank you!!!! Curve one: {32,0},{35 1.52},{45,7.62},{55,12.73},{90,21.08} Curve two: {32,24.64},{35,26.16}.{45,32.26},{55,37.34},{90,45 .72} Whoops didnt reply to ur comment
Originally Posted by KeatonBuddy Ok thank you!!!! Curve one: {32,0},{35 1.52},{45,7.62},{55,12.73},{90,21.08} Curve two: {32,24.64},{35,26.16}.{45,32.26},{55,37.34},{90,45 .72} Whoops didnt reply to ur comment curve 1 is $-0.00544151 x^2+1.03165 x-27.6779$ curve 2 is $-0.00541312 x^2+1.02809 x-2.94836$
Are you not at all concerned with whether or not that answer is correct? When I put x= 32 into $\displaystyle −0.00544151x^2+ 1.03165x−27.6779$, I get -0.2372, not 0.
Originally Posted by HallsofIvy Are you not at all concerned with whether or not that answer is correct? When I put x= 32 into $\displaystyle −0.00544151x^2+ 1.03165x−27.6779$, I get -0.2372, not 0. I checked a plot of the quadratic against the points. It's not perfect but it's pretty damn close. Could it be improved by increasing the order of the model? Sure. Is it necessary? Almost certainly not.
Originally Posted by romsek I checked a plot of the quadratic against the points. It's not perfect but it's pretty damn close. Could it be improved by increasing the order of the model? Sure. Is it necessary? Almost certainly not. Um if you dont mind can i get how you found this equation
Originally Posted by KeatonBuddy Um if you dont mind can i get how you found this equation mathematica's NonlinearModelFit[] function