I need to find the following equation in terms of y=f(x): ln(3-y)=3ln(2x+1)-x the bit that is stumpin me it the how to get the y out of the initial set of brackets to start the equation. Thanks for any help
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Originally Posted by wannberocketscientist I need to find the following equation in terms of y=f(x): ln(3-y)=3ln(2x+1)-x the bit that is stumpin me it the how to get the y out of the initial set of brackets to start the equation. Thanks for any help Not a bad question: Exponentiate each side:
Originally Posted by wannberocketscientist I need to find the following equation in terms of y=f(x): ln(3-y)=3ln(2x+1)-x the bit that is stumpin me it the how to get the y out of the initial set of brackets to start the equation. Thanks for any help First, a bit of "cleaning up." Now raise both sides to the base e and recall that : I'm sure you can finish from here. -Dan
thanks for the quick reply!
Originally Posted by wannberocketscientist thanks for the quick reply! You are welcome wannberocketscientist!
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