anyone help me on this.

the eigenvectors are 2,-1,3.

This is B,

1 1 1

2 1 2

3 2 4

This is B-1,

0 2 -1

2 -1 0

-1 -1 1

I cant seem to workout how you manage to get from B to B-1.

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- December 24th 2007, 05:22 AMnaisy18Diagonalisation of a matrix
anyone help me on this.

the eigenvectors are 2,-1,3.

This is B,

1 1 1

2 1 2

3 2 4

This is B-1,

0 2 -1

2 -1 0

-1 -1 1

I cant seem to workout how you manage to get from B to B-1. - December 24th 2007, 05:38 AMCaptainBlack
- December 24th 2007, 05:50 AMnaisy18
- December 24th 2007, 08:06 AMTKHunny
Naisy, what are you doing in this material? You simply MUST be able to find the inverse of a simple 3x3 matrix.

Cpt. Black used some terms with which you simply must be familiar. If you are not, you must look them up and get familiar. It will not serve you at all to remain absent this information. - December 24th 2007, 10:23 AMIsomorphism
Can't we use the given eigenvalues to make the computation a tad easier:confused:

- December 24th 2007, 04:29 PMgalactus
Here's a way to find an inverse, but it's rather cumbersome. May not be taught much these days. I don't know. It's comes from the

**adjoint**.

Using the cofactors:

From these we build a matrix:

Take the transpose and we get:

Now, finally,

So, we have - December 25th 2007, 06:52 AMIsomorphism