Yesterday I posted a qn. on subgroups. The answers really helped me.

I have one more ..

I didn't understand this qn. at all

What does it mean and how to do it?

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- December 15th 2007, 09:04 PMAmyOne more group Question
Yesterday I posted a qn. on subgroups. The answers really helped me.

I have one more ..

I didn't understand this qn. at all

What does it mean and how to do it? - December 15th 2007, 10:33 PMtopsquark
Sketch an equilateral triangle and plot a point at the center of it.

Note that if you rotate the triangle 120 degrees about this point the triangle looks the same as it initially did. This is the symmetry. Similarly for . ( would be the "identity" transformation. Obviously if you rotate the triangle by 0 degrees it looks the same as it did before you "rotated" it.)

For the "flips" sketch a line from the center of the triangle through vertex A. Note that we have reflection symmetry over this line: if we reflect the triangle over this line it looks the same as it did before. This is the element . Obviously we have the same kind of symmetry no matter which vertex we pick, so we also have and . (The and are symmetries about "horizontal" and "vertical" lines. These symmetries depend on the orientation of the square, obviously.)

See what you can do with these rotations and reflections for a pentagon. (Hint: You'll have 5 rotations and 5 reflections.)

-Dan - December 16th 2007, 10:05 AMAmy
Thanks for the reply.

So, is it some thing like

s={R0, R72,R154,R226,R298, FA, FB, FC,FD,FE}?? - December 16th 2007, 10:28 AMtopsquark
That'll do it!

Another one to watch out for (not present here) is "inversion" symmetry. The best way to describe this one is to let the center point of your figure be the origin. A group has inversion symmetry if you perform and and the figure looks the same as it did before the operation. The typical symbol for inversion is "i."

-Dan - December 18th 2007, 04:16 AMJaneBennet
In general, the symmetry group of a regular

*n*-gon will consist of*n*rotations and*n*flips. The rotations will be through a mulitple of degrees. For the flips, it depends on whether*n*is odd or even. If*n*is odd, all the flips will be about axes passing from one vertex to the midpoint of the opposite side. If*n*is even, half the flips will be about axes passing from one vertex to the opposite vertex and the other half will be about axes passing from the midpoint of one side to the midpoint of the opposite side.

The symmetry group of the regular*n*-gon (*n*≥ 3) is called the dihedral group of order 2*n*. Also, flips are more usually called “reflections”. :D

So, for the regular pentagon:

Quote:

Originally Posted by**Amy**