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Math Help - i need help with two questions <3

  1. #1
    Junior Member
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    i need help with two questions <3

    please help me solve these! i have an exam tomorrow! please explain the solutions ok ^_^



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  2. #2
    MHF Contributor
    Joined
    Apr 2005
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    F = (9/5)C +32

    The idea is to isolate C alone by itself, woth no attachments, on one side of the equation.
    32 is with the (9/5)C in the righthand side (RHS), so remove the 32 from there. Transpose the 32 to the lefthand side (LHS), or subtract 32 from both sides,
    F -32 = (9/5)C
    The C is attached to the fraction 9/5. Remove that 9/5 by dividing both sides by 9/5,
    (F -32) / (9/5) = C
    (5/9)(F -32) = C
    C = (5/9)(F -32) ------------answer.

    ---------------------------------------------------
    6 -(n +(1/9)x) = 7n

    Again, try anything to isolate n on one side of the equation.

    6 -n -x/9 = 7n
    6 -x/9 = 7n +n
    6 -x/9 = 8n
    Divide both sides by 8,
    (6 -x/9) / 8 = n
    ((6*9 -x) /9) / 8 = n
    ((54 -x) / 9) *1/8 = n
    (54 -x)*1 / (9*8) = n
    n = (54 -x) / 72 -------------answer.
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