Hello everyone. I received a take-home exam for my algebra class. I was doing the problems and I think I found a typo in the exam. The question is as follows:
Letbe a homomorphism and show
1, 2, or 3.
Now I though thatis a subgroup of
and hence, by Lagrange theorem, must divide 3003.
Nowcan have at most 6 elements (i.e. the order of
). But the only numbers less than or equal to 6 that divide 3003 are 1 and 3.
Also, ifimplies
maps two elements to the identity of
. This implies that the kernel has order 2. But the kernel of a homomorphism is a normal subgroup, and
has no normal subgroup of order 2.
Sois the only possibility???
Right?


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I need to take the real full exam. 
. Except the stuff on rings, factor rings, ideals, ideals of F[x]. Are you talking about that?