Results 1 to 2 of 2

Math Help - Orthogonality

  1. #1
    Member
    Joined
    Jun 2006
    Posts
    93

    Orthogonality

    If x=(x1,x2)^T, y=(y1,y2)^T, and z=(z1,z2)^T are arbitrary vectors in R^2 prove that

    a) x^Tx (x transpose x) >= 0
    So basically I got x1^2 + x2^2 >= 0

    Not sure where to go with this proof... thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Global Moderator

    Joined
    Nov 2005
    From
    New York City
    Posts
    10,616
    Thanks
    10
    Quote Originally Posted by pakman View Post
    If x=(x1,x2)^T, y=(y1,y2)^T, and z=(z1,z2)^T are arbitrary vectors in R^2 prove that

    a) x^Tx (x transpose x) >= 0
    So basically I got x1^2 + x2^2 >= 0

    Not sure where to go with this proof... thanks
    Because x_1^2\geq 0\mbox{ and }x_2^2\geq 0 because they are squares.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Orthogonality
    Posted in the Advanced Algebra Forum
    Replies: 2
    Last Post: November 2nd 2009, 04:41 PM
  2. Orthogonality
    Posted in the Differential Geometry Forum
    Replies: 1
    Last Post: October 30th 2009, 08:48 PM
  3. orthogonality
    Posted in the Advanced Algebra Forum
    Replies: 3
    Last Post: October 25th 2009, 10:58 PM
  4. Orthogonality
    Posted in the Advanced Algebra Forum
    Replies: 0
    Last Post: November 19th 2008, 12:34 PM
  5. Orthogonality
    Posted in the Advanced Algebra Forum
    Replies: 4
    Last Post: May 14th 2008, 11:20 PM

Search Tags


/mathhelpforum @mathhelpforum