Just wondering how i would solve (z^6) -2(z^3) +4 = 0 (where z is a complex number) any help would be greatly appreciated. Shaun
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Originally Posted by Shaun Gill Just wondering how i would solve (z^6) -2(z^3) +4 = 0 (where z is a complex number) any help would be greatly appreciated. Shaun Stage 1: Treat it as a quadratic in and use the quadratic formula. This will give you two complex roots. Stage 2:Convert each of the roots into polar form (that is write as: , then: RonL
thanx a lot. genius.
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