Just wondering how i would solve (z^6) -2(z^3) +4 = 0 (where z is a complex number)

any help would be greatly appreciated.

Shaun

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- Mar 22nd 2006, 05:38 AMShaun GillComplex number problem
Just wondering how i would solve (z^6) -2(z^3) +4 = 0 (where z is a complex number)

any help would be greatly appreciated.

Shaun - Mar 22nd 2006, 06:23 AMCaptainBlackQuote:

Originally Posted by**Shaun Gill**

formula.

This will give you two complex roots.

Stage 2:Convert each of the roots into polar form (that is write

as: , then:

RonL - Mar 22nd 2006, 06:25 AMShaun Gill
thanx a lot. genius.