# Math Help - Field acioms- division

1. ## Field acioms- division

Hello, I need some help on how to prove this using the field axioms of the real numbers

Given a and b with a =/ 0, there is exactly one x such that ax = b. This x is denoted as b/a.

Thanks in advance

2. Originally Posted by lds09
Hello, I need some help on how to prove this using the field axioms of the real numbers

Given a and b with a =/ 0, there is exactly one x such that ax = b. This x is denoted as b/a.

Thanks in advance
$ax=b$ then $a^{-1}(ax)=a^{-1}b$ then $(a^{-1}a)x=a^{-1}b$ thus $1x = a^{-1}b$ thus $x=a^{-1}b$.