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Thread: dimker dimim

  1. #1
    Jun 2013

    dimker dimim

    Let's say we have 2 vector space, U and V , over the field F. And we have Linear transformation T:U->V,
    Can someone give me the proof of dimU=dimKer+dimIm ?I have it in my notebook but I can't understand it . thank you
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  2. #2
    MHF Contributor

    Apr 2005

    Re: dimker dimim

    The kernel of T is, by definition, the set of all u in space U such that T(u)= 0. It is fairly easy to show that the kernel is a subspace. Choose a basis for the kernel and extend it to a basis for U. Call the subspace spanned by the extension U'. Then U= ker(T)+ U'. We can use that to show that any u in U can be written in a unique way as u1+ u2 where for u1 in the kernel and u2 is in U'. For any v in Im(T), there exist u in U such that T(u)= v. Write u= u1+ u2 where u1 and u2 are as before. Then T(u)= T(u1+ u2)= T(u1)+ T(u2)= T(u2)= v. Show that this is a "one-to-one" mapping of the image of T onto U'.
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