Does applying the Gram-Schmidt process to the standard basis {(1,0,0),(0,1,0),(0,0,1)} of V3(Complex) result in an orthonormal basis which is the same?

i.e. {y1,y2,y3) = {(1,0,0),(0,1,0),(0,0,1)}?

Printable View

- Nov 10th 2007, 07:20 AMUnoticedGram-Schmidt
Does applying the Gram-Schmidt process to the standard basis {(1,0,0),(0,1,0),(0,0,1)} of V3(Complex) result in an orthonormal basis which is the same?

i.e. {y1,y2,y3) = {(1,0,0),(0,1,0),(0,0,1)}? - Nov 10th 2007, 09:36 AMCaptainBlack
- Nov 10th 2007, 11:21 AMUnoticed
ye I tried it and got the same, I just wanted to know if it was right

- Nov 10th 2007, 11:29 AMCaptainBlack