Equivalent Algebraic Expressions.

Printable View

Nov 5th 2013, 12:51 PM
sepoto

Equivalent Algebraic Expressions.

I am trying to see right now how these became equivalent:

$\frac{1}{2}((x-a)^2+y_0^2)^-^1^/^2(2(x-a))=\frac{x-a}{\sqrt(x-a)^2+y_0^2}$

Thanks in advance...
Nov 5th 2013, 12:56 PM
SlipEternal

Re: Equivalent Algebraic Expressions.

$x^{-k} = \dfrac{1}{x^k}$ and $x^{1/n} = \sqrt[n]{x}$ (where $k$ is any real number and $n$ is a positive integer). Do you see it now?
Nov 5th 2013, 01:06 PM
sepoto

Re: Equivalent Algebraic Expressions.

$\frac{1}{2}*\frac{2(x-a)}{((x-a)^2+y_0^2)^1^/^2}$ ?

I think this is maybe it. Thank you for your reply.
Nov 5th 2013, 01:48 PM
HallsofIvy

Re: Equivalent Algebraic Expressions.

Quote:

Originally Posted by sepoto

I am trying to see right now how these became equivalent:

$\frac{1}{2}((x-a)^2+y_0^2)^-^1^/^2(2(x-a))=\frac{x-a}{\sqrt(x-a)^2+y_0^2}$

Thanks in advance...

I presume you know that $\frac{1}{2}(2)= 1$ . You should also know that $A^{1/2}= \sqrt{A}$ and $A^{-1/2}= \frac{1}{A^{1/2}}= \frac{1}{\sqrt{A}}$

All times are GMT -8. The time now is 10:54 AM.

Copyright © 2005-2017 Math Help Forum. All rights reserved.