I am trying to see right now how these became equivalent:

$\displaystyle \frac{1}{2}((x-a)^2+y_0^2)^-^1^/^2(2(x-a))=\frac{x-a}{\sqrt(x-a)^2+y_0^2}$

Thanks in advance...

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- Nov 5th 2013, 12:51 PMsepotoEquivalent Algebraic Expressions.
I am trying to see right now how these became equivalent:

$\displaystyle \frac{1}{2}((x-a)^2+y_0^2)^-^1^/^2(2(x-a))=\frac{x-a}{\sqrt(x-a)^2+y_0^2}$

Thanks in advance... - Nov 5th 2013, 12:56 PMSlipEternalRe: Equivalent Algebraic Expressions.
$\displaystyle x^{-k} = \dfrac{1}{x^k}$ and $\displaystyle x^{1/n} = \sqrt[n]{x}$ (where $\displaystyle k$ is any real number and $\displaystyle n$ is a positive integer). Do you see it now?

- Nov 5th 2013, 01:06 PMsepotoRe: Equivalent Algebraic Expressions.
$\displaystyle \frac{1}{2}*\frac{2(x-a)}{((x-a)^2+y_0^2)^1^/^2}$?

I think this is maybe it. Thank you for your reply. - Nov 5th 2013, 01:48 PMHallsofIvyRe: Equivalent Algebraic Expressions.