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Math Help - Algebra Problem with Exponents

  1. #1
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    Algebra Problem with Exponents

    \dfrac{3}{4} t^{-1/4} = \dfrac{1}{4} t^{-1/3} hint? How to solve for t?
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  2. #2
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    Re: Algebra Problem with Exponents

    cross multiply and use correctly the rules for the indices...
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  3. #3
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    Re: Algebra Problem with Exponents

    Hello, Jason76!

    \text{Solve for }t\!:\;\tfrac{3}{4}\,\!t^{-1/4} = \tfrac{1}{4}\,\! t^{-1/3}

    Multiply by 4t^{\frac{1}{3}}\!:\;4t^{\frac{1}{3}}\left(\tfrac{  3}{4}\,\!t^{-\frac{1}{4}}\right) \;= \;4t^{\frac{1}{3}}\left(\tfrac{1}{4}t^{-\frac{1}{3}}\right)

    . . . . . . . . . . . . . . . . . 3t^{\frac{1}{12}} \;=\;1

    . . . . . . . . . . . . . . . . . . t^{\frac{1}{12}} \;=\;\frac{1}{3}

    . . . . . . . . . . . . . . . . . . . t \;=\;\frac{1}{3^{^{12}}}
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