2,3-1,1 -1,0,1,1 2,1,3,-2 1,1,1,-1 Is there any way of quickly determining this?
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No. Row reductions will tell you soon, but I wouldn't call it "quickly".
Originally Posted by lord12 2,3-1,1 -1,0,1,1 2,1,3,-2 1,1,1,-1 Is there any way of quickly determining this? use expansion method: $\displaystyle det (A) = a_{i1}A_{i1} + a_{i2}A_{i2} + ... + a_{in}A_{in}$ this is expansion about the ith row..
Also, "no". Certainly, it can be determined using a few methods.
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