I have to prove that
D:=\mathbb{F}_{11^{5*61*103}} \rightarrow \mathbb{F}_{11^{5*61*103}}
 y \rightarrow y^3+3y^2+3y+3
is bijective. But how can I do this?

I know it has something to with the fact that all 11,5,61,103 are distinct primes so I can do something with the chinese remainder theorem that goes in the direction

D \cong \mathbb{F}_{{11}^5} \oplus \mathbb{F}_{{11}^{61}} \oplus \mathbb{F}_{{11}^{103}} but what theorem does that say? Or how does the right version go? I can't find such a statement into my algebra notes...

Could maybe please someone give me a hint?