Could someone help me with this proof? Thanks! Let G be a group, and H a subgroup of G. Ha = Hb iff ab^-1 is in H
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Originally Posted by chris27 Could someone help me with this proof? Thanks! Let G be a group, and H a subgroup of G. Ha = Hb iff ab^-1 is in H .
I do not like your proof Soltras. now so that means for some . The converse if almost identity.
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