Could someone help me with this proof? Thanks!

Let G be a group, and H a subgroup of G.

Ha = Hb iff ab^-1 is in H

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- Nov 6th 2007, 12:45 PMchris27cosets
Could someone help me with this proof? Thanks!

Let G be a group, and H a subgroup of G.

Ha = Hb iff ab^-1 is in H - Nov 6th 2007, 01:27 PMSoltras
- Nov 6th 2007, 01:59 PMThePerfectHacker
I do not like your proof Soltras.

$\displaystyle Ha = Hb$ now $\displaystyle a\in Ha$ so $\displaystyle a\in Hb$ that means $\displaystyle a=hb$ for some $\displaystyle ab^{-1} = h \in H$. The converse if almost identity.