"H is a subgroup of G, a is in H. Show that Ha = H."

Is this as simple as showing that since H is a group, all operations are closed within that group? Or is there more to it than that? If it's the latter, I'm stuck.

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- Jul 21st 2013, 02:42 PM #1

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- Jul 21st 2013, 02:59 PM #2
## Re: HH = H, etc.

- Jul 21st 2013, 04:45 PM #3

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## Re: HH = H, etc.

Right, that's just the definition of Ha.

Is it clear that $\displaystyle Ha\subseteq H~?$ Why?

Can you show $\displaystyle H\subseteq Ha~?$

- Jul 21st 2013, 05:35 PM #4

- Jul 21st 2013, 07:13 PM #5

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