How do I rearrange this for y?
log(10)y=3log(10)x+2
thx
In fact what you want is not clear
It may be written as
log 10y - 3 lof 10x = 2
log (10y)/( 1000 x ^3) = 2
If the log is to the base 10 then we have
(10y)/( 1000 x ^3) = 10 ^ 2 etc please be specific with your question so as to enable us to help and avoid guess work
Hello, JellyOnion!
Since the base is 10 (ten), we can drop the subscript.
$\displaystyle \text{Solve for }y\!:\;\log y \:=\:3\log x+2$
We have: .$\displaystyle \log y \;=\; 3\log x + 2\cdot 1 \;=\;3\log x + 2\log(10) $
. . . . . . . . $\displaystyle \log y \;=\;\log(x^3) + \log(10^2) \;=\;\log(x^3) + \log(100)$
. . . . . . . . $\displaystyle \log y \;=\;\log(100x^3)$
Therefore:. . .$\displaystyle y \;=\;100x^3$