# Math Help - Rearranging log equation

1. ## Rearranging log equation

How do I solve this equation for x?

3log(10)(4x-30)=3 Note: it's log base 10

I know that the answer is x=10 but have no idea how to get there!

2. ## Re: Rearranging log equation

$3\log(10)(4x-30)=3\\3(1)(4x-30)=3\\4x=31\\x=\frac{31}{4}$
I think you wrote your equation wrong.

3. ## Re: Rearranging log equation

I would first divide through by 3 to get:

$\log(4x-30)=1$

Convert to exponential form:

$4x-30=10^1=10$

Now solve for $x$.