Re: Bx=b showing consistency

Hey n22.

Hint: Reduce the matrix and if you get a rank of less than 3 (i.e. zeroes in the first three columns for a row), then see if the fourth corresponding value is zero or non-zero.

The idea is that if 0x + 0y + 0z != 0, then you know that you have an inconsistent system.

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Re: Bx=b showing consistency

Hi Chiro,

Finally I end up with this matrix: Attachment 28730

[x y z]=t[3 -2 -2] where t is some parameter which is an element of R..please not this is a column vector..if there is a parameter t doesnt that mean that there are an infinite number of solutions ?

Rank=dim(colA)=no leading ones =3

What does this mean for the matrix???

i guess this means its consistent then ....since there is a solution for each leading one

Quote:

Originally Posted by

**chiro** Hey n22.

Hint: Reduce the matrix and if you get a rank of less than 3 (i.e. zeroes in the first three columns for a row), then see if the fourth corresponding value is zero or non-zero.

The idea is that if 0x + 0y + 0z != 0, then you know that you have an inconsistent system.

Re: Bx=b showing consistency

Since you are reducing in terms of free parameters x, y, and z, then what did you get in terms of x,y,z for the final column? (You have all zeroes but they should be functions of x, y, and z).

If you want to check the answer, I suggest you get something like Maple or Mathematica (Maple is good for this problem).