Hi

After after doing row reduction on matrix[1 3; 2 2]

what would you get?

Im checking if method is completely misguided.

Thanks.

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- June 12th 2013, 03:29 PMn22row echelong reduction qusetion-for examination
Hi

After after doing row reduction on matrix[1 3; 2 2]

what would you get?

Im checking if method is completely misguided.

Thanks. - June 12th 2013, 03:37 PMtopsquarkRe: row echelong reduction qusetion-for examination
- June 12th 2013, 04:10 PMn22Re: row echelong reduction qusetion-for examination
this matrix was formed in order to find an eigenvector or basis using a given eigenvalue .

got[1 3;0 -4] after some reductions ...which involved ensuring theres a zero beneath the first leading entry..

row2/-4 then gives [ 1 3 ;0 1]

now assigning parameters y=t

x=-3t;y=t

then [x ;y]=t[-3;1]

eigenvector then in [-3;1] - June 13th 2013, 06:45 AMHallsofIvyRe: row echelong reduction qusetion-for examination
Yes, that is correct for "row-reduction" but I don't know what you mean about "finding eigenvectors". You

**cannot**find eigenvectors (or eigenvalues) by row reduction!

In this particular problem, it is easy to see that which is NOT a multiple of ([3, 1]. [-3, 1] is NOT an eigenvector for this matrix!

(Here, the eigenvalues are and . Eigenvectors corresponding to eigenvalue are multiples of and eigenvectors corresponding to eigenvalue are multiples of ).