Hi there,
I have something such as:
(1/2 + i[sqrt3]/2)^60
I know using De Moivre's theorem I have:
z^n = r^n (cos(ntheta) + isin(ntheta)
with n=the power and r=modulus of the complex number
And with r=1 I get
1(cos(20pi) + isin(20pi))
And using Euler's theorem I get:
e^i20pi = 1
However, I am confused on why e^i20pi = 1 (I know this is the answer because of the solutions provided). Could anyone help explain this to me? Or help with an easier way of achieving the answer 1?
Thank you.