Hi guys I am stuck on something,

Find the equation of the plane p containing the point P(0;2;3) and normal to the line with parametric

form x = 1 + 2t; y = 0; z = t.

So norm is (1,0,0) + t(2,0,1)?

Next do I have to define another point say, R on plane so-

vector PR will be perpendicular to norm direction vector and-

PR x n = 0 (cross product of 2 perp. vectors)..??

If this is the right logic how do I use the norm in the form I have? I think I'd be able to do this if I had the norm as a 3 number direction vector, not (1,0,0) + t(2,0,1)..

Am I right in saying that as a plane is Ax + By + Cz = D, norm (x,y,z) provides the coefficients in this formula and point P(x,y,z) gives the rest of the information to algebraically solve?