Write the quadratic function in standard form. Identify the vertex. y = f(x) = -(x^2 + 4x - 2) please help
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Considering f(x) as ax^2+bx+c=0, a<0, D>0, so graph is downward parabola. a= -1 b=-4 c=2 vertex is at (-2,6)
Originally Posted by sciencepal Considering f(x) as ax^2+bx+c=0, a<0, D>0, so graph is downward parabola. a= -1 b=-4 c=2 vertex is at (-2,6) hey i know this is not mithread but can you please me explain how you got the vertex?
Originally Posted by captaincrunch383 hey i know this is not mithread but can you please me explain how you got the vertex? nevermind sir, i figured it out.
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