Find all real zeros of the function algebraically.
f(x)= x^4 - x^3 - 15x^2
help anyone?
Shakarri meant that one, $\displaystyle x^2(x^2-x-15)$
now you have in the brackets a second degree equation, it's impossible that you can not find the zeros from that one, try it,
ps: oops, we might have answered in the same time