Thread: parametric equation of the line through a point and parallel to a vector

can you pleaase check and let me know if i have done the below question correctlly, if not any help would be appreciated

Find the parametric equation of the line through the point (3,-1)and parallel to v = (3,1,-2)

Assuming that the points (3, -1) were from another vector.
equation is

X=(3,-1,0)+ t (3,1,-2)
that is x=3+t3
y=(-1)+t
z=(-2)t

this is the line through the points (3,-1)

Originally Posted by flametag3

can you pleaase check and let me know if i have done the below question correctlly, if not any help would be appreciated
Find the parametric equation of the line through the point (3,-1)and parallel to v = (3,1,-2)
Assuming that the points (3, -1) were from another vector.
equation is
X=(3,-1,0)+ t (3,1,-2)
that is x=3+t3
y=(-1)+t
z=(-2)t

this is the line through the points (3,-1)

You are mixing apples and oranges; $\displaystyle \mathbb{R}^2\text{ with }\mathbb{R}^3$.

So the question makes no sense.

Originally Posted by Plato

You are mixing apples and oranges; $\displaystyle \mathbb{R}^2\text{ with }\mathbb{R}^3$.

So the question makes no sense.

Last time I checked, Plato, any point or vector in 2D space is the same as any point or vector in 3D space on the plane where z = 0. So the 2D vector (3, -1) IS the same as the 3D vector (3, -1, 0).

To the OP, your answer is correct

Originally Posted by Prove It

Last time I checked, Plato, any point or vector in 2D space is the same as any point or vector in 3D space on the plane where z = 0. So the 2D vector (3, -1) IS the same as the 3D vector (3, -1, 0).

That is total nonsense.

No, completely logical actually