I am a little confused as to how to find the line of intersection of two planes
x + y + z -1 = 0
2x + y -z + 3 = 0
should i be using gaussian elimination for this ?but from what i am reading about gaussian elimination the top row wil multiple answers
The simplest thing to do, I think, is to add the two equations, eliminating z: 3x+2y+ 2= 0 so that 2y= -2- 3x and then y= -1- (3/2)x. Putting that into the first equation, x+ (-1 - (3/2)x)+ z- 1= -(1/2)x+ z= 0 so that z= (1/2)x.
The line or intersection is given by y= -1- (3/2)x or z= (1/2)x. Or if you prefer, take t= (1/2)x so that x= 2t, y= -1- 3t, z= t.