If,

ab/(a+b) = 2

ac/(a+c)=5

bc/(b+c)=4

then find a+b+c.

I'd really appreciate a step by step solution.

Results 1 to 5 of 5

- April 18th 2013, 05:00 AM #1

- Joined
- Feb 2013
- From
- US
- Posts
- 33
- Thanks
- 1

- April 18th 2013, 05:41 AM #2
## Re: This problem is ridiculous

Hi there,

We would solve for one variable and after that replace it in the original equation in order to have only one variable equation:

You can solve for a or for b, I will show you the example for both:

Now, solve for a, replace the value of a in the initial equation and solve for b, then try for the other examples,

dokrbb

hint - you will have and , check them in the first equation

- April 18th 2013, 06:31 AM #3

- Joined
- Feb 2013
- From
- US
- Posts
- 33
- Thanks
- 1

- April 18th 2013, 07:16 AM #4
## Re: This problem is ridiculous

This is not correct. The problem is that this equaton simply yields , so it does not yield a solution for a.

Here's how to do it. Once you have , use the same process on the equation to get . Now you have equatons for a and c in terms of b; sub them into and solve for b. Then you can sub the solution back into the other two equation to get values for a and c.

Despite the suggestion in the previous post and .

- April 18th 2013, 08:32 AM #5

- Joined
- Apr 2013
- From
- Canada
- Posts
- 42
- Thanks
- 2

## Re: This problem is ridiculous

If you're having trouble following ebaines' post, here's the process to figuring out a, b, and c.

1. Isolate a in equation 1

2. sub it into equation 2

3. Isolate isolate b in equation 2

4. sub it into equation 3

5. equation 3 will only have the variable c. Isolating c will yield its value.

6. sub in your value for c into equation 2 to find the value of b

7. sub in your value for b into equation 1 to find the value of a