If,

ab/(a+b) = 2

ac/(a+c)=5

bc/(b+c)=4

then find a+b+c.

I'd really appreciate a step by step solution.

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- Apr 18th 2013, 06:00 AMRuyHayabusaThis problem is ridiculous
If,

ab/(a+b) = 2

ac/(a+c)=5

bc/(b+c)=4

then find a+b+c.

I'd really appreciate a step by step solution. - Apr 18th 2013, 06:41 AMdokrbbRe: This problem is ridiculous
Hi there,

We would solve for one variable and after that replace it in the original equation in order to have only one variable equation:

You can solve for a or for b, I will show you the example for both:

Now, solve for a, replace the value of a in the initial equation and solve for b, then try for the other examples,

dokrbb

hint - you will have and , check them in the first equation ;) - Apr 18th 2013, 07:31 AMRuyHayabusaRe: This problem is ridiculous
Thanks a lot!

- Apr 18th 2013, 08:16 AMebainesRe: This problem is ridiculous
This is not correct. The problem is that this equaton simply yields , so it does not yield a solution for a.

Here's how to do it. Once you have , use the same process on the equation to get . Now you have equatons for a and c in terms of b; sub them into and solve for b. Then you can sub the solution back into the other two equation to get values for a and c.

Despite the suggestion in the previous post and . - Apr 18th 2013, 09:32 AMHowDoIMathRe: This problem is ridiculous
If you're having trouble following ebaines' post, here's the process to figuring out a, b, and c.

1. Isolate a in equation 1

2. sub it into equation 2

3. Isolate isolate b in equation 2

4. sub it into equation 3

5. equation 3 will only have the variable c. Isolating c will yield its value.

6. sub in your value for c into equation 2 to find the value of b

7. sub in your value for b into equation 1 to find the value of a