f(x) = x³ - 6x² + x - 5
(x+2)= f(-2) = (-2)³ - 6(-2)² + (-2) - 5 =
-8 - 24 - 2 - 5 = -39
Is this correct? I can't work out the answer for the first formula
Yes that is correct.
Thus $\displaystyle (x+2)$ does not divide $\displaystyle f(x)$. So $\displaystyle -39$ must be the remainder.
Surely you can find $\displaystyle (3)^3-6(3)^2+(3)-5=~?$