Determine the remainder when x³-6x²+x-5 is divided by: a. X+2 b. X-3 Hi I was wondering if someone can help me with these revision questions.
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Originally Posted by Andrew187 Determine the remainder when x³-6x²+x-5 is divided by: a. X+2 b. X-3. If then if then is a factor, so it divides . Thus what is
Last edited by Plato; Apr 15th 2013 at 03:03 AM.
f(x) = x³ - 6x² + x - 5 (x+2)= f(-2) = (-2)³ - 6(-2)² + (-2) - 5 = -8 - 24 - 2 - 5 = -39 Is this correct? I can't work out the answer for the first formula
Originally Posted by Plato If then if then is a factor, so it divides . Thus what is That actually doesn't help the OP. The remainder theorem states that for a polynomial function P(x) is divided by (x - a), the remainder is equal to P(a).
Originally Posted by Andrew187 f(x) = x³ - 6x² + x - 5 (x+2)= f(-2) = (-2)³ - 6(-2)² + (-2) - 5 = -8 - 24 - 2 - 5 = -39 Is this correct? I can't work out the answer for the first formula Yes that is correct. Thus does not divide . So must be the remainder. Surely you can find
Originally Posted by Plato Yes that is correct. Thus does not divide . So must be the remainder. Surely you can find its -29 But how come your formula is different to my first formula have I wrote it wrong?
Originally Posted by Andrew187 But how come your formula is different to my first formula ? How is it different?
Originally Posted by Plato Yes that is correct. Thus does not divide . So must be the remainder. Surely you can find Is that sum for (x-3)?
Originally Posted by Andrew187 Is that sum for (x-3)? That is the remainder when is divided by .
Originally Posted by Plato Yes that is correct. Thus does not divide . So must be the remainder. Surely you can find 27-24+3-5=1 is this correct? or is it this 27-72+3-5= -43
Last edited by Andrew187; Apr 15th 2013 at 04:13 AM.
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