Hi. In comparisons, can work with logarithms in the usual manner? (Hoping, of course, my usual manner is the correct manner.)

Is this valid:

(Edit: assuming , if that matters.)

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- March 28th 2013, 02:04 PMinfraRedcomparisons and logarithms
Hi. In comparisons, can work with logarithms in the usual manner? (Hoping, of course, my usual manner is the correct manner.)

Is this valid:

(Edit: assuming , if that matters.) - March 28th 2013, 05:16 PMchiroRe: comparisons and logarithms
Hey infraRed.

One approach you could try is showing d/dx [ln(x+2)] < d/dx (x+2) for all x >= 1 and show that ln(1+2) < 1+2.