# imaginary numbers

• March 23rd 2013, 06:20 AM
needhelpnow
imaginary numbers
need to solve 6-6i/-9i

came up with the answer 2/3 + 2/3i

What am I doing wrong. It's showing up as incorrect.

Thank you.
(Hi)
• March 23rd 2013, 06:28 AM
Gusbob
Re: imaginary numbers
You're missing a negative sign

$\frac{6-6i}{-9i}=\frac{2-2i}{-3i}=\frac{2-2i}{-3i}\cdot \frac{i}{i}=\frac{2i-2i^2}{-3i^2}=\frac{2i+2}{3}$

• March 23rd 2013, 08:29 AM
Soroban
Re: imaginary numbers
Hello, needhelpnow!

Quote:

Simplify: $\frac{6-6i}{-9i}$

Came up with the answer 2/3 + 2/3i

What am I doing wrong? It's showing up as incorrect.

Your answer, $\tfrac{2}{3} + \tfrac{2}{3}i$, is correct.

. . it might be read as: $\tfrac{2}{3} + \tfrac{2}{3i}$