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Math Help - integral 1

  1. #1
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    Unhappy integral 1

    y=sqrt(x+1),x=1,y=-1
    i have to find a volume(certain integral) of geometric body which is showed (produced) by y=sqrt(x+1) rotation about y=-1...integral 1-slide1.jpg
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  2. #2
    Behold, the power of SARDINES!
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    Re: integral 1

    Quote Originally Posted by mathe26 View Post
    y=sqrt(x+1),x=1,y=-1
    i have to find a volume(certain integral) of geometric body which is showed (produced) by y=sqrt(x+1) rotation about y=-1...Click image for larger version. 

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    The radius (or distance) between the functions and the line y=-1 is

    r=\sqrt{x+1}-(-1) \implies r=\sqrt{x+1}+1

    Now to find the volume of the solid of rotation use the disk method

    \int_{-1}^1 \pi r^2dx=\int_{-1}^1 \pi (\sqrt{x+1}+1)^2dx
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  3. #3
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    Re: integral 1

    sorry but i do not know to continue,can u help a little bit more
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