y=sqrt(x+1),x=1,y=-1 i have to find a volume(certain integral) of geometric body which is showed (produced) by y=sqrt(x+1) rotation about y=-1...
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Originally Posted by mathe26 y=sqrt(x+1),x=1,y=-1 i have to find a volume(certain integral) of geometric body which is showed (produced) by y=sqrt(x+1) rotation about y=-1... The radius (or distance) between the functions and the line y=-1 is $\displaystyle r=\sqrt{x+1}-(-1) \implies r=\sqrt{x+1}+1$ Now to find the volume of the solid of rotation use the disk method $\displaystyle \int_{-1}^1 \pi r^2dx=\int_{-1}^1 \pi (\sqrt{x+1}+1)^2dx$
sorry but i do not know to continue,can u help a little bit more
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