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Math Help - Dominant term help

  1. #1
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    Dominant term help

    Hi everyone.

    I have the below sequence and I'm confused as to what is it's dominant term.

    Dominant term help-spock.gif n = 1,2........

    Is it n^5 as the n^6 is (1/n^6)?

    Apologies in advance as I don't think this is classed as an advanced algebra question
    Last edited by jennybee; March 9th 2013 at 04:41 AM.
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  2. #2
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    Re: Dominant term help

    Yes, it is x^5, because \frac{1}{n^6}=n^{-6}.
    Thanks from jennybee
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  3. #3
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    Re: Dominant term help

    Thankyou
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  4. #4
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    Re: Dominant term help

    If your ultimate objective is to find the limit, as n goes to infinity, divide both numerator and denominator by the "dominant" term, x^5.
    Thanks from jennybee
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  5. #5
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    Re: Dominant term help

    Quote Originally Posted by HallsofIvy View Post
    If your ultimate objective is to find the limit, as n goes to infinity, divide both numerator and denominator by the "dominant" term, x^5.
    That was what I did next , then apply the combination rules which gave me the limit to be 2.
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