1. ## Dominant term help

Hi everyone.

I have the below sequence and I'm confused as to what is it's dominant term.

n = 1,2........

Is it n^5 as the n^6 is (1/n^6)?

Apologies in advance as I don't think this is classed as an advanced algebra question

2. ## Re: Dominant term help

Yes, it is $x^5$, because $\frac{1}{n^6}=n^{-6}$.

Thankyou

4. ## Re: Dominant term help

If your ultimate objective is to find the limit, as n goes to infinity, divide both numerator and denominator by the "dominant" term, $x^5$.

5. ## Re: Dominant term help

Originally Posted by HallsofIvy
If your ultimate objective is to find the limit, as n goes to infinity, divide both numerator and denominator by the "dominant" term, $x^5$.
That was what I did next , then apply the combination rules which gave me the limit to be 2.