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Math Help - Re-arranging an inequality

  1. #1
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    Re-arranging an inequality

    I am trying to solve the inequality

    [(4x - x^2 - 7) / (x^2 - 1)] >_ 3

    I am still at the re-arranging stage and I get up to the point of

    [(4x - x^2 - 7) / (x^2 - 1)] -3 >_ 0 which I understand how to get to.

    But I do not understand how to get the below line of.

    [(4x - 4x^2 - 4) / (x^2 - 1)] >_ 0
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  2. #2
    Forum Admin topsquark's Avatar
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    Re: Re-arranging an inequality

    Quote Originally Posted by jezb5 View Post
    I am trying to solve the inequality

    [(4x - x^2 - 7) / (x^2 - 1)] >_ 3

    I am still at the re-arranging stage and I get up to the point of

    [(4x - x^2 - 7) / (x^2 - 1)] -3 >_ 0 which I understand how to get to.

    But I do not understand how to get the below line of.

    [(4x - 4x^2 - 4) / (x^2 - 1)] >_ 0
    You have two expressions here: One with all the variables and the three. Put:
     \frac{ 4x - x^2 - 7}{x^2 - 1 } + \frac{ -3(x^2 - 1)}{x^2 - 1 }

    -Dan
    Last edited by topsquark; March 4th 2013 at 12:46 PM.
    Thanks from jezb5
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  3. #3
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    Re: Re-arranging an inequality

    Quote Originally Posted by topsquark View Post
    You have two expressions here: One with all the variables and the three. Put:
     \frac{ 4x - x^2 - 7}{x^2 - 1 } + \frac{ -3(x^2 - 1)}{x^2 - 1 }

    -Dan

    Thank you, that makes sense
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