# Math Help - Linear Algebra help

1. ## Linear Algebra help

${v_{1}, v_{2}, v_{3} }$ is a basis for a three dimensional real vector space V. Show that the set ${v_{1} + v_{2} , v_{2} + v_{3}, v_{3}+ v_{1} }$ is also a basis for V.

I am finding it really hard ot understand the concept of finding bases, and my notes dont make sense, am not even sure where to start, do i first find a spanning set ?

2. ## Re: Linear Algebra help

Note that if $w_1 = v_1 + v_2, w_2 = v_2+v_3, w_3 = v_3+v_1$ then

$w_1-w_2+w_3 = 2v_1$ and so $v_1 = (1/2)(w_1-w_2+w_3)$

The same can be done to find a linear combination of w's for $v_2,v_3$. Can you finish?

3. ## Re: Linear Algebra help

Hi Tweety!

To show the new set is a basis for V, you should show that each of the original vectors can be constructed from the new set.
Does that make sense?

4. ## Re: Linear Algebra help

so some how show $v_{1}$ = $v_{1} + v_{2}$ ? Still not sure where to start though

5. ## Re: Linear Algebra help

Note that if $w_1 = v_1 + v_2, w_2 = v_2+v_3, w_3 = v_3+v_1$ then

$w_1-w_2+w_3 = 2v_1$ and so $v_1 = (1/2)(w_1-w_2+w_3)$

The same can be done to find a linear combination of w's for $v_2,v_3$. Can you finish?
But thats not a linear combination ?

6. ## Re: Linear Algebra help

The new set that ILikeSerena is referring to is your new set of w vectors. If you can show that each v vector is a linear combination of w vectors, then you are done. You are done because let t be an arbitrary vector in V. since t is a vector in V, with v's as the basis, t can be expressed as $t = av_1 + bv_2 + cv_3$. If you can show that $v_1,v_2,v_3$ are linear combinations of w vectors, then you can replace each $v_i$ with w's.

I have given you one such combination. (Verify by replacing each w vector by the sum of v vectors and algebra) In this case by simple replacement $t = a[(\frac{1}{2})(w_1-w_2+w_3)] + bv_2 + cv_3$

Combine like terms after you express $v_2$ and $v_3$ in terms of w's and observe the arbitrary vector t in the vector space V is a linear combination of w's, hence the set of w vectors is a basis.