i have an inequality e^{a} => e^{b} can i take take the log of this inequality? and is the following inequality correct for every "a" and "b"? log (e^{a}) => log (e^{b}) then a => b thanks a lot.
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Yes, both logarithm and exponential are increasing functions so if $\displaystyle e^a\ge e^b$ then $\displaystyle a\ge b$. (It would be better to use ">=" for "greater than or equal to". "=>" looks too much like "implies".)
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