Hi,

I'm trying to calculate this series!

Attachment 27214

a and b are two constants.

is there any answer for this series??

Any Answer is helpful.

hasti

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- February 24th 2013, 03:48 AMhasticalculating a series
Hi,

I'm trying to calculate this series!

Attachment 27214

a and b are two constants.

is there any answer for this series??

Any Answer is helpful.

hasti - February 24th 2013, 04:26 AMBashyboyRe: calculating a series
Well, seeing as b is a constant, that implies that as m goes through the different values, from one to infinity, b is unaffected. So, what can we do with it?

EDIT: If it isn't immediately evident why b remains unaffected as m goes through its different values, and what we can do with it, let's calculate a partial sum of this series. Let's find the sum for just

What do you notice about "a" and "b," as m goes from 1 to 3? - February 24th 2013, 04:41 AMBashyboyRe: calculating a series
I edited my post, hasti.

EDIT: Actually, I don't know how helpful it will be. I misread what sort of series you have. - February 24th 2013, 04:48 AMhastiRe: calculating a series
Yes, It's correct. Then now, We should calculate this series when b is eliminated!

But i don't know how to do it!

Attachment 27223 - February 24th 2013, 04:56 AMBashyboyRe: calculating a series
Well, b isn't eliminated, it's just factored out of the series. Are you sure there isn't suppose to be an addition sign between a and m^2?

- February 24th 2013, 05:10 AMhastiRe: calculating a series
let me to explain with an example!

we know that

Attachment 27225

now i should find an equivalent for

Attachment 27226

thanks - February 24th 2013, 05:38 AMhastiRe: calculating a series
we don't need any extra sign between a and m^2. a is a coefficient for m^2 and (a*m^2) is a power for e.

thanks for your attention.